Question by "Statistics-And-Probability"

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/quiz?quiz action-takeQuiz&quiz probduid ONAPCOA8010100000049bacfc00900008ctx-japaulson-00128ck-m 1554308693405 0AA 6. Analysis of variance with unequal sample sizes Mental health professionals often use structured interviews when diagnosing patients. A director of a mental health clinic would like to compare the effectiveness of three different diagnostic interviews in diagnosing post-traumatic stress disorder: the Structural Clinical Interview for DSM Disorders (SCID), which is the gold standard for a psychiatric diagnosis by a trained clinician; the Clinician-Administered PTSD Scale (CAPS), which is the gold standard in post-traumatic stress disorder assessment; and the Schedules for Clinical Assessment in Neuropsychiatry (SCAN), a semistructured diagnostic interview administered by clinically trained interviewers. The clinic director performs an experiment in which 12 clinical psychology interns are randomly assigned to three groups: the first consisting of 3 interns, the second 4 interns, and the third 5 interns. Interns in the first group are trained to diagnose patients using SCID, interns in the second group are trained to diagnose patients using CAPS and interns in the third group are trained to diagnose patients using SCAN. After traning, each intern's diagnostic accuracy is recorded using a seven-point scale The data and means for the diagnostic accuracy scores for each of the three groups are presented in the table below Diagnostic Interviews Group 1 Group 2 Group 3 SCID CAPS SCAN 4.62564 5.26 5.31 5.27 5.53 4.81 4,82 4.63 4.57 4.74 5.29 nj Mean Grand Mean(gm) 4.9067 5.43754.8040 5.0408 The sample sizes in the experiment above are e/quiztquiz actionstakeQuiz&quiz probduid-ONAPCDA8010100000049bacfc00900008 cte-japaulson-00128ck-m 1554308693405 ne sampie sizes in the experiment apove are The three diagnostic interviews define three populations of interest. You will use analysis of variance (ANOVA) to test the hypothesis that the three population means are equal. The results of your analysis will be presented in the ANOVA table below ANOVA Table Source SS Groups Error Total df MS 0.3587 0.4444 1.1508 Go through the following steps to complete the ANOVA table. (Hint: Your answers will be most accurate if you do not round at intermediate steps. However, if you must round, round to at least two decimal places more than the number of decimals desired in your final answer.) 1. Enter the value of the total sum of squares, sum of squares due to groups, and then the sum of squares due to error in the ANOVA table. 2. Enter all of the degrees of freedom in the ANOVA table. 3. Enter the values of the mean square for groups, the mean square for error, and the F-test statistic in the ANOVA table. F Distribution We were unable to transcribe this image /quiz?quiz action-takeQuiz&quiz probduid ONAPCOA8010100000049bacfc00900008ctx-japaulson-00128ck-m 1554308693405 0AA 6. Analysis of variance with unequal sample sizes Mental health professionals often use structured interviews when diagnosing patients. A director of a mental health clinic would like to compare the effectiveness of three different diagnostic interviews in diagnosing post-traumatic stress disorder: the Structural Clinical Interview for DSM Disorders (SCID), which is the gold standard for a psychiatric diagnosis by a trained clinician; the Clinician-Administered PTSD Scale (CAPS), which is the gold standard in post-traumatic stress disorder assessment; and the Schedules for Clinical Assessment in Neuropsychiatry (SCAN), a semistructured diagnostic interview administered by clinically trained interviewers. The clinic director performs an experiment in which 12 clinical psychology interns are randomly assigned to three groups: the first consisting of 3 interns, the second 4 interns, and the third 5 interns. Interns in the first group are trained to diagnose patients using SCID, interns in the second group are trained to diagnose patients using CAPS and interns in the third group are trained to diagnose patients using SCAN. After traning, each intern's diagnostic accuracy is recorded using a seven-point scale The data and means for the diagnostic accuracy scores for each of the three groups are presented in the table below Diagnostic Interviews Group 1 Group 2 Group 3 SCID CAPS SCAN 4.62564 5.26 5.31 5.27 5.53 4.81 4,82 4.63 4.57 4.74 5.29 nj Mean Grand Mean(gm) 4.9067 5.43754.8040 5.0408 The sample sizes in the experiment above are
e/quiztquiz actionstakeQuiz&quiz probduid-ONAPCDA8010100000049bacfc00900008 cte-japaulson-00128ck-m 1554308693405 ne sampie sizes in the experiment apove are The three diagnostic interviews define three populations of interest. You will use analysis of variance (ANOVA) to test the hypothesis that the three population means are equal. The results of your analysis will be presented in the ANOVA table below ANOVA Table Source SS Groups Error Total df MS 0.3587 0.4444 1.1508 Go through the following steps to complete the ANOVA table. (Hint: Your answers will be most accurate if you do not round at intermediate steps. However, if you must round, round to at least two decimal places more than the number of decimals desired in your final answer.) 1. Enter the value of the total sum of squares, sum of squares due to groups, and then the sum of squares due to error in the ANOVA table. 2. Enter all of the degrees of freedom in the ANOVA table. 3. Enter the values of the mean square for groups, the mean square for error, and the F-test statistic in the ANOVA table. F Distribution

Seen 8 months ago Ava Linda 1 answers

Unlike most packaged food products, alcohol beverage container labels are not required to show calorie or nutrient content. An article reported on a pilot study in which each of 58 individuals in a sample was asked to estimate the calorie content of a 12 oz can of beer known to contain 153 calories. The resulting sample mean estimated calorie level was 191 and the sample standard deviation was 87. Does this data suggest that the true average estimated calorie content in the population sampled exceeds the actual content? Test the appropriate hypotheses at significance level 0.001. State the appropriate null and alternative hypotheses. Ο Η. Holl = 153 Ha: L # 153 O Ho: u = 153 Ha: [ > 153 O Ho: 4 = 153 Ha: s 153 O Ho: 4 = 153 Ha: 4 < 153 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. O Do not reject the null hypothesis. There is not sufficient evidence that the true average estimated calorie content of this beer exceeds the actual content. O Reject the null hypothesis. There is not sufficient evidence that the true average estimated calorie content of this beer exceeds the actual content. O Do not reject the null hypothesis. There is sufficient evidence that the true average estimated calorie content of this beer exceeds the actual content. O Reject the null hypothesis. There is sufficient evidence that the true average estimated calorie content of this beer exceeds the actual content. You may need to use the annronriate table in the Annendiy of Tables to answer this question

Seen 9 months ago Lee White 1 answers

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